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8y^2-57y+7=0
a = 8; b = -57; c = +7;
Δ = b2-4ac
Δ = -572-4·8·7
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-55}{2*8}=\frac{2}{16} =1/8 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+55}{2*8}=\frac{112}{16} =7 $
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